Proof the Earth is round

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Maybe I'm doing it wrong as others have claimed it takes them the same amount of time. I don't find myself putting off changing strings on a fixed bridge 🤷‍♂️

Exactly

I could probably change strings in about 5 minutes if I really hustled, but I like to take my time and clean the board and wipe down the finish etc and stretch my strings. The guys that say they can do Floyds just a s quick have probably done it a lot due to gigging and such and just don't even think about it.

I on the other hand....
 
I like Floyds myself, even though I don’t have many guitars left that have them.
If a string breaks by the bridge you just have to unclamp the nut and give the tuning peg a couple turns until you have enough slack to put it back in the bridge.
Ready for the next song.
 
1) Water curving: water is just a pile of molecules hanging out together. The shape of the surface is determined by the shape of the force pulling on them, it'll pull the molecules around until all the molecules have the lowest energy possible. For a flat surface with a uniform downwards force, that's a level surface. For a sphere with a spherically symmetric force pulling towards the center of the sphere, the water forms a spherical shell around the sphere. For a 5 gallon bucket that you spin round-n-round, creating the imaginary "centrifugal force" pointing towards the bucket bottom in the water's perspective, it sticks to the bottom of the bucket even as the bucket passes above your head.
This seems to suggest that if my five gallon bucket is convex at the bottom then if I swing it round and round, it will become convex at the surface i.e curved water? Or would I have to be swinging it faster?

2) I'm not certain about the 8 in/ sq-mi thing yet, still looking into it. Looks like that is an approximation that assumes we're dealing with very small distances relative to the earth's radius though. One thing that catches people out with this is doing the math as if your eyeball was on the ground, instead of calculating based on your eyes being 5-6ft off the ground.
It seems like it would be definitively stated, since everything else is, but I have seen varying numbers online, which also works to leave my conclusion that it is just a math and measurement-estimate based theory more than it is demonstrable, fully provable one. If I assume everything is an estimate then it doesn't seem to offer any use for me to buy into a globe model. I'm all ears on what you are able to dig up on this one.

3) I'd have to review it, but I think the answer is no. It's not that the earth moves under your feet when you jump, it has to do with the fact that angular speed (which should be constant for every part of the globe, basically how many degrees you rotate each second) is related to linear speed (how many feet you travel each second) by a factor of the radius. In SI units it'd be r ✕ ω, where r is the radius of the circular path you're moving along, and ω is the angular speed. The circle you travel gets bigger as you get closer to the equator since you're farther from the earth's axis, so things on the equator have a higher linear speed than things at the poles, and the in-between bits are in-between. If this speed difference isn't compensated for as you move from pole to equator or vice versa, then your path will be screwy. Wikipedia has a cool gif:
This is going to take me some time for me to process it, since in google's GIF is a disc not a sphere but my initial impression also leads me to think that every gunshot is basically a curve ball then, flying in conjunction with a spinning earth but also leads me to question how if there is space between me and the ground over a given amount of time, like the bullet flying, then technically how am I not being affected by that though it be in a miniscule way? Is there some sort of distance+velocity that must be reached, and if so, why wouldn't it work on a smaller scale at less speed since it is related to earth spinning? Technically measurable, correct?

So in my mind if I am a long jumper my theoretical best jump would be when I made jumps from east to west, so that more earth is spinning past me while I am suspended between earth and sky. If coriolis effect must be compensated for on a marksman's shot to reach the bullseye is the calculation altered if he is shooting West to East? Or only north to south? Is the distance of the bullet's travel further west to east than it is east to west since it is having to "catch up" to the spin of the earth?

How can the bullet flying be affected, but not the person jumping, or a helicopter, or flying a plane for example? Are flight plans laid out with a spinning earth in mind? Like the bridge builder, there is a lot of claims on both sides about this.
 
I like Floyds even thought I don't use really use the bar. I learned to avoid whammys in general on the POS guitars I had as a teen as tuning immediately went crap.
I like the Bigsby for the low string tension but have found if I raise the tailpiece on a tune-o-matic I can get it just as slinky. I used to like the old six point Fender trem floated but I would bash on those trem bars like a 9th grade science teacher bashes on a flat earther and they eventually would break off in the block. I could drill em' out but the last time the threads wound up stripped. I could wrap a little tape and press fit them but trem is mostly a great way to make your guitar out of tune and break strings or in the case of a Floyd, tone suck you, so I just quit using them and eventually switched to Gibson style guitars anyways.
 
I like Floyds myself, even though I don’t have many guitars left that have them.
If a string breaks by the bridge you just have to unclamp the nut and give the tuning peg a couple turns until you have enough slack to put it back in the bridge.
Ready for the next song.
All I read here is BABICZ. :love: :LOL:
 
All I read here is BABICZ. :love: :LOL:
Funny you mentioned algorithms earlier, I think my phone picked up on all your babicz posts because Facebook recommended me to befriend him this morning lol.
His shop isnt far from where my father in law lives, I should ask to check out his shop sometime.

I think he had something to do with Steinberger hardware at one point too, maybe it’s time for you to go headless….
 
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Funny you mentioned algorithms earlier, I think my phone picked up on all your babicz posts because Facebook recommended me to befriend him this morning lol.
:LOL: Someone is watching us, if only to sell us more stuff we probably don't really need, but yeah a BABICZ bridge or tailpiece is a pretty sweet piece of hardware.
 
This makes sense but it can't be demonstrated. In your example, the water in the spun bucket would be level with the base of the bucket. Would be great if you could devise a gravity machine and stick it in the center of a ball and then pour some water on it!
The particle nature of water and the effects of forces on particles and the statistical mechanics that large ensembles of particles obey can in fact be demonstrated. In my example, I believe it would actually be slightly convex. Plus off-center since it's getting pushed along by the bucket. As far as a gravity machine, the bucket thing is a way to get a (near) central force like gravity in the water's reference frame, just with an outwards instead of inwards direction.
The object would be hidden because of the limitations of human sight and perspective. There is plenty of amateur footage of ships hidden by 'earths curvature', yet are brought into view with a powerful enough zoom lens.
This just restates what I said. If zooming in makes it re-appear, than it is close enough to not be hidden behind the curve, and the zoom just overcame one of the other reasons things disappear.
Take a look here. Refraction effects also play a role in observable distance. https://www.metabunk.org/curve/https://www.metabunk.org/curve/
VBF was asking about the curve of the earth, not why we can sometimes see things would be hidden. I'm aware that refraction plays a role in visibility, and have brought that up earlier in this thread.
Yet if you shoot a cannonball straight up it will land within a few feet of where it was launched.
Double-checked, I goofed and worked things out for a spinning disk like the wikipedia gif. On a sphere, going straight up involves some change of radius relative to the axis of rotation unless you're on a pole over the course of your air-time. On a spinning disk, if you jump straight up then your radius from the rotation axis doesn't change. So on a sphere I'd expect there to be some change in landing position, @VonBonfire.
You will say the Coriolis effect is negligible at this scale
I'd have to do the calculations before saying that. Would have to review first. It's been a bit since I did classical mechanics, as is evident from the earlier goof. At the scale of VBF hopping up and down in his driveway though, over the timescale he'd do it before getting bored and going to play his twins, and given tolerance of a human jump, I'd expect it to be negligible.
but that is basically the same answer for everything about globe earth -- everything becomes apparent at scales too vast to directly demonstrate (Except for the nonsense about the direction of toilets flushing I guess).
We've been down this road before in this thread, and I was unsatisfied with the way you handled the discussion. It is a big part of the reason why I think you're probably not arguing in good faith. Because of that, I don't think it's worth my time to engage with you beyond this point. I may occasionally as I feel like it, but don't expect it. I'm primarily focusing on engaging with VBF for now, since at least in my direct interactions with him there still seems to be the possibility of a good-faith discussion. Thanks for catching the Coriolis goof though.
 
Vibrato, trem. It’s the same thing. And he definitely met Eddie.
vibrato pitches up and down
tremelo pulses back and forth
slight difference but to us guitar (wanna be) players it is the same
Ed could do both and tap and hammer on better than Ace
Love Ace Frehley though - big reason I love electric guitar even though I don't know what I'm doing :lol:
 
vibrato pitches up and down
tremelo pulses back and forth
slight difference but to us guitar (wanna be) players it is the same
Ed could do both and tap and hammer on better than Ace
Love Ace Frehley though - big reason I love electric guitar even though I don't know what I'm doing :lol:
Ace had great “Vibrato”. More melodic than Ed in my opinion.
 
This seems to suggest that if my five gallon bucket is convex at the bottom then if I swing it round and round, it will become convex at the surface i.e curved water?
I think you wouldn't even need a convex bucket bottom, it would happen with a flat-bottomed bucket too. Same way the surface of a glass of water is unaffected by what shape the bottom of the glass is. If it needs to be stated again though, I'm shooting from the hip at the moment with these couple questions (already goofed on one), and if you want further details on one then we can go into that one specifically. Just trying to get something down for now in the approximate direction of the answer.
It seems like it would be definitively stated, since everything else is, but I have seen varying numbers online, which also works to leave my conclusion that it is just a math and measurement-estimate based theory more than it is demonstrable, fully provable one. If I assume everything is an estimate then it doesn't seem to offer any use for me to buy into a globe model. I'm all ears on what you are able to dig up on this one.
It's a definitive thing you can work out from the spherical shape of the earth, but I haven't taken the time to work it out myself yet, and haven't verified the calculations I've found to my satisfaction yet. The approximation stuff comes into play after you have the exact solution (well, exact if the earth is a perfect sphere and not ever so slightly skewed from that) and realize that certain terms only contribute a little bit to the answer unless the distances are large, so if you're working with small distances you don't really have to care about them.
This is going to take me some time for me to process it, since in google's GIF is a disc not a sphere but my initial impression also leads me to think that every gunshot is basically a curve ball then, flying in conjunction with a spinning earth but also leads me to question how if there is space between me and the ground over a given amount of time, like the bullet flying, then technically how am I not being affected by that though it be in a miniscule way? Is there some sort of distance+velocity that must be reached, and if so, why wouldn't it work on a smaller scale at less speed since it is related to earth spinning? Technically measurable, correct?
Note that I goofed on this one because I worked things out for the gif, which has a spinning disc not a sphere, which @Bad Brain pointed out. Jumping up on a spinning sphere, unless you're at a pole, involves your radius from the axis of rotation changing over your "flight time", so there should be some deviation from your starting point. The exact magnitude I'd have to do the calculations to see, but at the scale of your driveway (which I assume is not that big?), how long you're willing to jump for, and the inherent tolerances to how straight you can jump up and down as a human, I'm doubtful you'd notice it that way.
So in my mind if I am a long jumper my theoretical best jump would be when I made jumps from east to west, so that more earth is spinning past me while I am suspended between earth and sky.
I think so.
If coriolis effect must be compensated for on a marksman's shot to reach the bullseye is the calculation altered if he is shooting West to East? Or only north to south? Is the distance of the bullet's travel further west to east than it is east to west since it is having to "catch up" to the spin of the earth?
I think the west-east shot would also be affected.
How can the bullet flying be affected, but not the person jumping
'cause I goofed, that's how. Sorry about that, shouldn't have tried to shoot from the hip on a topic I haven't worked through for some time while also tired.
 
t's a definitive thing you can work out from the spherical shape of the earth, but I haven't taken the time to work it out myself yet, and haven't verified the calculations I've found to my satisfaction yet. The approximation stuff comes into play after you have the exact solution (well, exact if the earth is a perfect sphere and not ever so slightly skewed from that) and realize that certain terms only contribute a little bit to the answer unless the distances are large, so if you're working with small distances you don't really have to care about them.
It would be cool if you had the time to look at it closely. There are several curvature calculators online but I have no idea if they are accurate per what is taught at the university level. Here's one:

https://dizzib.github.io/earth/curve-calc/?d0=2.38&h0=1&unit=imperial

Note that I goofed on this one because I worked things out for the gif, which has a spinning disc not a sphere, which @Bad Brain pointed out. Jumping up on a spinning sphere, unless you're at a pole, involves your radius from the axis of rotation changing over your "flight time", so there should be some deviation from your starting point. The exact magnitude I'd have to do the calculations to see, but at the scale of your driveway (which I assume is not that big?), how long you're willing to jump for, and the inherent tolerances to how straight you can jump up and down as a human, I'm doubtful you'd notice it that way.
No worries. Lemme know if you find something chart -image wise that would help me visualize this better.

As for the jumping, I'm not expecting to see noticeable differences, I'm just suggesting that on a theoretical measurement of extreme precision it would be a slight deviation per your remarks about the bullet and the long jumper. I'd def like to hear more on this and the curve calculations if/when you have time.

One of the things me and monkey man were debating was a theoretical circumnavigation. He claimed that on a disc I would be forced to make constant rudder adjustments to the left to maintain an eastward course, which makes some sense going around a circle, but thinking on it, does a pilot or flight planner then make a theoretical course correction for the curvature since it is a similar principle just working on a different axis? If the pilot doesn't go "down" to match the curve, he would be increasing in altitude as he flew. I realize that compass' and the plane's instruments would be the automatic compensator but I'm guessing in the theoretical that both these things would hold true in their respective disc/ball models.
 
The particle nature of water and the effects of forces on particles and the statistical mechanics that large ensembles of particles obey can in fact be demonstrated. In my example, I believe it would actually be slightly convex. Plus off-center since it's getting pushed along by the bucket. As far as a gravity machine, the bucket thing is a way to get a (near) central force like gravity in the water's reference frame, just with an outwards instead of inwards direction.
Do you mean concave? At some point the water would leave the bucket entirely, IE start climbing up the walls as rotational speed increases. But in any case the nature of water is such that the opposite, IE convex curvature, cannot be demonstrated in an experiment with the forces that we are able to manipulate.
This just restates what I said. If zooming in makes it re-appear, than it is close enough to not be hidden behind the curve, and the zoom just overcame one of the other reasons things disappear.
I will follow up on this, as I believe there exists plenty of amateur footage where the distance is identified to be such that the ship should not be able to be seen. But we don't really need to, because we have the Chicago footage from the Michigan shore (which as I've criticized is claimed to be a mirage.)
On a sphere, going straight up involves some change of radius relative to the axis of rotation unless you're on a pole over the course of your air-time. So on a sphere I'd expect there to be some change in landing position
Okay, but when this experiment is performed, such as with a cannonball, it is never demonstrated to be beyond the margin of error when accounting for wind and other variables. If you are aware otherwise, please let me know.

We've been down this road before in this thread, and I was unsatisfied with the way you handled the discussion. It is a big part of the reason why I think you're probably not arguing in good faith. Because of that, I don't think it's worth my time to engage with you beyond this point. I may occasionally as I feel like it, but don't expect it. I'm primarily focusing on engaging with VBF for now, since at least in my direct interactions with him there still seems to be the possibility of a good-faith discussion. Thanks for catching the Coriolis goof though.
If you could let me know specifically where you were unsatisfied I'd be happy to address it. I think it is a bad idea to assume others are not arguing in good faith, at least when they are asking you to show them how and they want to respond. Otherwise it comes across (to me at least) as a way to avoid further engagement in a debate one is losing.
 
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Do you mean concave? At some point the water would leave the bucket entirely, IE start climbing up the walls as rotational speed increases. But in any case the nature of water is such that the opposite, IE convex curvature, cannot be demonstrated with an experiment with the forces that we are able to manipulate.

I will follow up on this, as I believe there exists plenty of amateur footage where the distance is identified to be such that the ship should not be able to be seen. But we don't really need to, because we have the Chicago footage from the Michigan shore (which as I've criticized is claimed to be a mirage.)

Okay, but when this experiment is performed, such as with a cannonball, it is never demonstrated to be beyond the margin of error when accounting for wind and other variables. If you are aware otherwise, please let me know.


If you could let me know specifically where you were unsatisfied I'd be happy to address it. I think it is a bad idea to assume others are not arguing in good faith, at least when they are asking you to show how and then want to respond to a specific. Otherwise it comes across (to me at least) as a way to avoid further engagement in a debate one is losing.
@7704A I will vouch that Bad Brain is arguing in good faith. We have a few people arguing in good faith on both sides here, which is enjoyable, but we also have a few here that think anyone who doesn't believe as they do is a dumbfuck so there has been some heated moments and possibly some wrong wires crossed up. Anyways, I'm happy to hear more good discussion!!!
 
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