Series? Or parallel?

  • Thread starter Thread starter JackBootedThug
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JackBootedThug

JackBootedThug

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For two 8 ohm speakers. Any reason to pick one over the other? Just bi-curious…🤔🤪🤮
 
Depends on what you want your final ohm-age to be? 🤔
 
8
Edit-I guess it doesn’t matter but probably 8 is best for my setup….
 
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In series, you add the numbers together.
Speaker 1 plus speaker 2 equals your impedance.
8+8=16

In parallel, it's a little more complicated. The formula is (X×X)÷(X+X). We can simplify it when the speakers are the same. X²÷2X.
(8×8)=8²=64
(8+8)=2(8)=16
64÷16=4

If you use the correct formula, it helps with mismatched speakers too.
In series, 8+4=12
In Parallel, (8×4)÷(8+4)=2.66 because 32÷12=2 1/3
 
Fast answer on identical impedances is that two identical items in parallel have exactly half the impedance of each one individually. No math (well, halving) necessary.
 
I like asking here before doing a three second google search… because I value the homies opinions more than google!!!!
 
That's actually a good idea. Definitely skip the AI search as I stumble into a lot of outright wrong answers with that. At least, go to wikipedia and peruse their answers. Those are generally correct.
 
If running a solid state amp I would do parallel for 4 ohms. Tube amp I do series for 16. That way I can run two cabs for 8 ohms when needed.
 
I like asking here before doing a three second google search… because I value the homies opinions more than google!!!!

I've had Google send me right back to Rig-Talk when I ask questions, so you're not wrong. We are the sorce of the AI answers anyways.
 
Ai keeps saying that the angle of the dangle is perpendicular to the trickle of the dickle…wtf 😜🤔
 
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